What is distinct prime factor in simple words?
Find total number of distinct primes in the prime factorization of number 27300?
To find the total number of distinct primes in the prime factorization of the number 27300, we begin by factoring 27300.
Step 1: Divide by 2 (smallest prime)
27300 is an even number, so divide by 2:
27300÷2=1365027300 div 2 = 13650
13650 is still even, so divide by 2 again:
13650÷2=682513650 div 2 = 6825
Now, 6825 is odd, so we stop dividing by 2.
Step 2: Divide by 3 (next smallest prime)
Check if 6825 is divisible by 3 (sum of digits = 6 + 8 + 2 + 5 = 21, which is divisible by 3):
6825÷3=22756825 div 3 = 2275
Now, 2275 is not divisible by 3.
Step 3: Divide by 5 (next smallest prime)
Since 2275 ends in 5, it’s divisible by 5:
2275÷5=4552275 div 5 = 455
455 also ends in 5, so divide by 5 again:
455÷5=91455 div 5 = 91
Now, 91 is not divisible by 5.
Step 4: Divide by 7 (next smallest prime)
Check if 91 is divisible by 7:
91÷7=1391 div 7 = 13
Now we have 13, which is a prime number.
Step 5: Prime factorization of 27300
We now have the complete prime factorization of 27300:
27300=22×3×52×7×1327300 = 2^2 times 3 times 5^2 times 7 times 13
Step 6: Count the distinct primes
The distinct primes in the factorization are: 2, 3, 5, 7, and 13.
Thus, the total number of distinct primes is 5.